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@recuraki

# Codeforces Round #615 B. Collecting Packages

More than 1 year has passed since last update.

シンプルな問題

# 概要

• x,yの二次元平面があり、たかだかマスは1000程度である
• 0,0にロボットがおり、UかRのアクションを行える
• 100個のnx, nyが順番に与えられる
• ロボットは各nx,nyを通過できるか判定せよ。YESの場合、例を１つ表示せよ。

# アプローチ

• 今の座標をx,yに対して、x <= nx かつ y <= nyであるかを判定。NGなら、"NO"が確定
• 可能なら、x軸の差分だけRを、y軸の差分だけUを表示する
```q = int(input())
for q in range(q):
qq = int(input())
dat = []
s = ""
for _ in range(qq):
x, y = map(int, input().split())
dat.append([x, y])
dat.sort(key=lambda a: a[0] + a[1])
cx, cy = 0, 0
f = True
for i in range(qq):
x, y = dat[i][0], dat[i][1]
if x < cx or y < cy:
f = False
break
s += "R" * (x - cx)
s += "U" * (y - cy)
cx,cy = dat[i][0], dat[i][1]
if f:
print("YES")
print(s)
else:
print("NO")

```

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Help us understand the problem. What is going on with this article?