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Promiseを直列で実行する

Last updated at Posted at 2014-07-12

並列で実行したい場合は Promise.all([promise...]) すれば事足りるんだけど、直列で実行しようとするとちょっとややこしい。

# 実行すると1秒後に実行回数をprintするPromise化された関数
cnt = 0
f = -> new Promise (done) ->
  setTimeout (->
    console.log 'done', cnt++
    done()
  ), 1000

# fを直列に4回実行する
promises = [f, f, f, f]
seq = promises.reduce ((ret, p) ->
  ret.then p
), promises.shift()()

seq.then => console.log 'finish'

実行結果

done 0
done 1
done 2
done 3
finish 

Array.prototype.reduceでthenを繋ぐのが肝

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