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Itertoolsを使って重複あり順列の全てのパターンを列挙する

Last updated at 2018-04-27Posted at 2018-02-21

qiita.py

 import itertools
 list(itertolls.product("abc",repeat=3))
>>>[("a","a","a"),("a","a","b")...("c","c","c")] #全部で27パターン

list(itertolls.product("abc"),repeat=2))とlist(itertolls.product("abc")("abc")("abc"))は同じ意味。