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Haskellで直角三角形のタプルをつくる

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まずは、1〜100の3辺x, y ,zの組み合わせをつくる。

[(x, y, z) | x <- [1..100], y <- [1..100], z <- [1..100]]

ここで、zを斜辺だとすると、xとyはzより小さいことになる。その組み合わせをつくると、

[(x, y, z) | z <- [1..100], y <- [1..z], x <- [1..z]]

x,y,zの順番を少し入れ替えていることに注意。
xとyは、yの方を長辺だとすると、さらにこう書ける。

[(x, y, z) | z <- [1..100], y <- [1..z], x <- [1..y]]

あとは、x^2 + y^2 = z^2を満たす組み合わせを抽出する。

[(x, y, z) | z <- [1..100], y <- [1..z], x <- [1..y], (x * x + y * y == z * z)]

以上で完成。

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