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Haskellでループのbreak

Haskell

Posted at 2012-06-23

継続モナド使おう。

import Control.Monad
import Control.Monad.Cont

main :: IO ()
main = do
  (`runContT` const (return ())) $ do
    callCC $ \k -> do
      forM_ [1..10] $ \i -> do
        when (i > 5) $ k ()
        liftIO $ print i

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