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[Groovy]複数のリストから全ての組み合わせを持ったリストを生成する

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#概要
数学で言うところの順列(Permutation)と組み合わせ(Combination)です。
それぞれeachPermutationeachCombinationというメソッドがあります。

今回の例は単純に数字を使っていますが、例えば何かしらの検索サービスを実装する際に、Aの検索結果は100件で、AにBという検索条件を足した場合は80件、AにBとCとう検索条件を追加した場合は20件、といった使い方が出来るんじゃないのかな。。。と想像します。


// 組み合わせ
List combinationList = []
[[1,2], [3,4]].eachCombination { combinationList << it }
assert [[1,3], [2,3], [1,4], [2,4]] == combinationList


// 順列
List permutationList = []
[1, 2, 3].eachPermutation { permutationList << it }
assert  [[1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1]] == permutationList

// 組み合わせから順列を生成
List combinationToPermutation = []
combinationList.each { List combination ->
    combination.eachPermutation{ combinationToPermutation << it }

}

assert [[1, 3], [3, 1], [2, 3], [3, 2], [1, 4], [4, 1], [2, 4], [4, 2]] == combinationToPermutation

#参考
eachCombination
eachPermutation

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