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入れ子dictの全keyを取得するメソッド

Last updated at Posted at 2017-04-24

コメントによりスマートな書き方があるので、是非参考にしてください。

test= {"w": {"y":{"z":1}},"ww":1, "www":{"yy":1}}

def allkeys(a):
    keys = a.keys()
    values = a.values()

    t = []
    for v in values:
        if isinstance(v, dict):
            t.extend(allkeys(v))

    result = [i for i in keys]
    result.extend(t)
    return result

r = allkeys(test)
print(r)


実行結果
['ww', 'www', 'w', 'yy', 'y', 'z']


キー名に親のキーを付けた場合

test= {"w": {"y":{"z":1}},"ww":1, "www":{"yy":1}}

def parentnema(k, v):
    return k +"."+ v

def allkeys(a):
    keys = a.keys()
    values = a.values()

    t = []
    for k in keys:
        v = a.get(k)
        if isinstance(v, dict):
            t.extend(map(lambda z: k + "." + z, allkeys(v)))

    result = [i for i in keys]
    result.extend(t)
    return result

r = allkeys(test)
print(r)

実行結果
 ['ww', 'www', 'w', 'www.yy', 'w.y', 'w.y.z']

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