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PHPUnitでコンストラクタを呼ばずにテストする

Last updated at Posted at 2013-02-12

テスト対象コード

SampleClass.php
<?php

class SampleClass
{
    public function __construct()
    {
        exit;
    }

    public function hoge()
    {
        return TRUE;
    }
}
  • hoge()がTRUEを返すことを検証したい

テストコード

SampleClassTest.php
<?php

require_once 'SampleClass.php';

class SampleClassTest extends PHPUnit_Framework_TestCase
{
    public function testHogeReturnTrue()
    {
        $this->class = new SampleClass();
        $this->assertTrue($this->class->hoge());
    }
}

テスト実行結果

$ phpunit SampleClassTest.php 
PHPUnit 3.6.10 by Sebastian Bergmann.
  • コンストラクタが呼ばれexitが実行されるために検証結果が得られない

テストコード

SampleClassTest.php
<?php

require_once 'SampleClass.php';

class SampleClassTest extends PHPUnit_Framework_TestCase
{
    public function testHogeReturnTrue()
    {
        $class = $this->getMockBuilder('SampleClass')
                      ->setMethods(NULL)
                      ->disableOriginalConstructor()
                      ->getMock();

        $this->assertTrue($class->hoge());
    }
}

テスト実行結果

$ phpunit SampleClassTest.php
PHPUnit 3.6.10 by Sebastian Bergmann.

.

Time: 0 seconds, Memory: 2.75Mb

OK (1 test, 1 assertion)
  • MockBuilderを活用しdisableOriginalConstructor()を設定することで検証結果を得ることができた
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