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上と左の合計(再帰)

Last updated at Posted at 2014-06-09

本番で書いた汚いコードはこちら。http://qiita.com/cielavenir/items/ab6c3e9a482c7b42519e

本番中に再帰は考えていたものの、焦ってしまい実装に手が回らなかった。

律儀にclassとしたが、Rubyはmainインスタンスにインスタンス変数を追加できるので必要ではなかったかもしれない。

hena22_rec.rb
#!/usr/bin/env ruby
#http://qiita.com/Nabetani/items/34bf2a05099a47e193b6
#http://nabetani.sakura.ne.jp/hena/ord22irrpas/
class Hena22
	def initialize(cells)
		@cells=cells
		@memo={}
	end
	def solve(x,y)
		return 0 if x<0||y<0
		return 1 if x==0&&y==0
		if @memo[[x,y]]
			return @memo[[x,y]]
		end
		cell=@cells.find{|e|e[:x1]<=x&&x<e[:x2] && e[:y1]<=y&&y<e[:y2]}
		if cell
			if cell[:x1]==x && cell[:y1]==y
				cells_for_val={}
				val=0
				(cell[:y1]...cell[:y2]).each{|_y|
					adjacent_cell=@cells.find{|e|e[:x1]<=x-1&&x-1<e[:x2] && e[:y1]<=_y&&_y<e[:y2]}
					if !adjacent_cell||!cells_for_val.include?(adjacent_cell)
						cells_for_val[adjacent_cell]=1 if adjacent_cell
						val+=solve(x-1,_y)
					end
				}
				(cell[:x1]...cell[:x2]).each{|_x|
					adjacent_cell=@cells.find{|e|e[:x1]<=_x&&_x<e[:x2] && e[:y1]<=y-1&&y-1<e[:y2]}
					if !adjacent_cell||!cells_for_val.include?(adjacent_cell)
						cells_for_val[adjacent_cell]=1 if adjacent_cell
						val+=solve(_x,y-1)
					end
				}
				return @memo[[x,y]]=val
			else
				return @memo[[x,y]]=solve(cell[:x1],cell[:y1])
			end
		else
			return @memo[[x,y]]=solve(x-1,y)+solve(x,y-1)
		end
	end
end

if $0==__FILE__
	STDOUT.sync=true
	while gets
		a,b=$_.chomp.split(':')
		column,row=a.split('x').map(&:to_i)
		cells=!b ? [] : b.split(',').map{|e|
			l,t,w,h=e.split('').map(&:to_i)
			#高さ/幅から端点の座標に変更
			{:x1=>l.to_i,:x2=>l.to_i+w.to_i,:y1=>t.to_i,:y2=>t.to_i+h.to_i}
		}
		puts '%02d'%[Hena22.new(cells).solve(column-1,row-1)%100]
	end
end
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